Study of the compounds formed by the interaction of sugars with the hydroxides of the alkaline earth metals

Abstract

#1. Lime unites with glucose, fructose, maltose and lactose respectively to give one Compound only, consisting of one molecule of lime combined with one molecule of the sugar.

#2. Lime fructose exists as a hexahydrate and di_ hydrate, lime glucose as a dihydrate, while lime maltose and lime lactose give only a monohydrate. When apparently completely dehydrated, these compounds retain from a half to one molecule of water.

#3, As methyl glucoside, methyl fructoside, methyl maltoside and methyl lactoside do not unite with the alkaline earths, it is probably that the above lime sugars are formed by the interaction of the reducing group of the sugar with lime to give a 'lime glucoside' and water.

#4. No trace of a and B forms can be encountered in the lime glucosides.

#5. Sucrose unites with lime to give a monolime_ monosucrose which exists as a hexahydrate and a dihydrate, but which may not be a true compound, and dilime-monosucrose and trilime monosucrose, which are probably hexahydrates.

Strontia and sucrose give monostrontia_monosucrose which is probably a hexahydrate, and distrontia_ monosucrose which is anhydrous.

Baryta and sucrose yield only anhydrous monobaryta- monosucrose.

#6. It is suggested that the compounds of sucrose with the alkaline earths are neither alcoholates nor colloids, but of the same type as the double salts obtained when sucrose unites with potassium chloride.